Explanation: x-coordinate of vertex: #x = (-b/2a) = 2/2 = 1# y-coordinate of vertex: #y = f (1) = 1 - 2 - 15 = -16# Answer link You can reuse this answer

Equation is 5 (x-1)^2+9y=45 It appears you are seeking a graph of a vertical parabola.

Feb 23, 2016 · y = (x - 3 )^2 - 3 >The equation of a parabola in vertex form is y =a (x-h)^2 + k where (h , k ) are the coordinates of the vertex.

36 (y-5)=-7 (x-4)^2 We know that, the eqn. of a parabbola S having its vertex at (h,k) is given by, S : (y-k)=a (x-h)^2. So, in our case, S : (y-5)=a (x-4)^2. To determine the constant a, we use …

How do you write the standard form of the equation of the parabola that has (-1/4, 3/2) vertex and (-2,0) point?

How do you graph the parabola #y=x^2-3x# using vertex, intercepts and additional points?

Dec 13, 2015 · How do you find the center, vertices, foci and eccentricity of x2 4 + y2 9 = 1? Precalculus Geometry of an Ellipse Identify Critical Points

Mar 27, 2017 · Vertex form = gives you the vertex of a parabola. There are two ways to get the vertex form. One is to complete the square given an equation in standard form, the other is to …

May 6, 2016 · In graphing #y=4 (x-3)^2 -2#, the vertex of the parabola is at what point?

The graph of f (x) is a parabola with vertex at x= (-b)/ (2a) x_"vertex" = (-1)/ (2* (1/4))=-2 Since a=1/4>0 the f (x_"vertex" ) is the absolute minimum of f (x) :. f_min = f (-2) = 4/4-2-8= -9 …